WELCOME TO 2025! Here are some recreational-maths number facts about 2025 and a series of puzzles all related to 2025. Enjoy!
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Contents of this page

2025

Factors

2025 is

Digits

2025 is:

Figurate Numbers

2025 is

Pythgorean triangles

2025:

Runsums

2025:

Puzzles

Divisors:

  1. 52 × 34 × 1 uses all the digits 1,2,3,4 and 5.
    Find a formula for 2025 which uses 0,1,2,3,4,5 and 6
    Hence find on that uses all digits 0,1,...,n for n=7, 8, 9!
    Answer 2025 = 60 × 1 × 34 × 52
    = (1+6)0 × 34 × 52
    Another solution is
    2025 = 70×1&× 34 × 52
    2025 = (1 + 6 + 7)0 × 34 × 52
    2025 = (1 + 6 + 7 + 8)0 × 34 × 52
    2025 = (1 + 6 + 7 + 8 + 9)0 × 34 × 52
  2. 2025 is the first odd number with 15 divisors.
    Find 5 smaller numbers also with 15 divisors?
    Answer Since 2025 is the first (smallest) odd number, any smaller ones must be even:
    144 = 24×32,
    324= 22×34,
    400 = 24×52,
    784 = 24×72,
    1936 = 24×112,
    See A030633
  3. How many divisors has 1208?
    Answer 1208 = 224×38×58
    so it has (24+1)(8+1)(8+1) = 25×92 = 2025
    For the divisors count for the other powers of 120, see A100176

Squares:

  1. 2025 is a square number (452) which is also a multiple of a cube (33×75). What is the smallest such number? What is the next after 2025?
    Answer Smallest is 16 = 42 = 23×2
    The next after 2025 is 2401 = 492 = 73×7
    See A320965
  2. Earlier it was stated that 2025 is a sum of 3 sets of squares in 9 ways. One way is 42 + 282 + 352. FInd the other 8 sets.
    Answer 5 8 44, 5 20 40, 6 15 42, 6 30 33, 8 19 40, 13 16 40, 16 20 37, 20 28 29

Digits:

  1. 2025 = 45×45 so is a product of two numbers ending in 5. If the smallest two such are 5×5 = 25 and 5×15 = 75 find the next four.
    How are these related to a sum of odd numbers?
    Answer 5×5 = 25,
    5×15 = 75,
    5×25 = 125,
    5×35 = 175,
    5×45 = 225,
    5×55 = 275, ... A053742
    Each is the sum of the odd numbers in the range 10..19, 20..29, 30..39, ...:
     1 +  3 +  5 +  7 +  9 = 25
    11 + 13 + 15 + 17 + 19 = 75,
    21 + 23 + 25 + 27 + 29 = 125 ...
  2. 2025 is a 4-digit square number starting wih 2. What is the next but having 5-digits?
    Answer 20164 See A067472
  3. Find 4 other square numbers that only use the digits 0, 2 and 5 or a subset of these.
    Answer In order they are: 25, 225, 2025, 2500, 22500, 55225, 202500, 250000, 255025, 555025, 2002225, 2205225, 2250000, 5522500, 20205025, 20250000, 25000000 ... Those that do not end in 0 are in A058426
  4. 2025 = 452 is still a square number if we increase each of its digits by 1 since 3136 = 562. Such numbers will therefore not contain a digit 9. Find one such number smaller than 2025 and one larger number with this property.
    Answer 25 = 52 and 36 = 62
    13225 = 152 and 24336 = 562
    For others see A061843
  5. 2025 is made up of 20 and 25. If we add these two halves (20+25=45) and square the sum (45²), we get 2025 back again. Find another number which can be split into two parts of equal length, added then squared and gives the original number.
    Answer 3025, 9801, 494209, ... see A238237

Figurate Number Puzzles:

  1. Write out the multiplication table a×b for a and b from 1 to 2.
    What is the sum of all the products in the table?
    What is the sum if we have rows for a and columns for b from 1 to 3? ANd what about a 4-by-4 multiplcation table?
    Guess a formula for the product's total for n rows and n columns.
    What is the sum for n=9?
    Answer
    12
    24
    1+2+2+4=9
    =32
    123
    246
    369
    1+2+3 + 2+4+6 + 3+6+9 = 36
    = 62
    n rows by n columns
    The first row is 1+2+...+n = Tri(n) = n(n+1)/2
    The second row is 2+4+...+2n = 2 Tri(n) = m(n+1)
    ...
    The last row is n+2n+...+n×n = n Tri(n) = n n(n+1)/2
    the sum of all rows is (1+2+...+n)Tri(n) = Tri(n)2

    The sum of the products in a 9x9 table is Tri(9)2 = 452 = 2025

  2. How many rectangles of any shape (including squares) can you draw using the lines of a grid which is n squares by n squares? Try it for 1 square, a grid of 2x2, of 3x3.
    How many possible rectangles are there in a 9x9 grid of squares?
    Answer
     
    A 1x1 grid has just 1 square: total 1

      
      
    A 2x2 grid of squares has 4@1x1, 2@1x2, 2@2x1, 1@2x2: total 9=32

       
       
       
    A 3x3 grid of squares has 9@1x1, 6@1x2, 6@2x1, 4@2x2, 3@1x3, 3@3x1,
    2@2x3, 2@3x2, 1@4x4:total 36=62

    In general there are Tri(n)2 possible rectangles. See A000537

    In a 9x9 grid of squares there are Tri(9)2 = 452 = 2025

Binary:

  1. 2025 is the square of 45 and 45 is 1011012 in binary and a palindrome. Find the other square numbers n2 smaller than 2025 where n is also a binary palindrome.
    Answer
    0 1 9 25 49 81 225 289 441 729 961 1089 2025 A192775
    n 0 1 3 5 7 9 15 17 21 27 31 33 45A006995
    n2 0 1 11 101 111 1001 1111 10001 10101 11011 11111 100001 101101

Runs

For more on Runs of natural numbers and their sums (runsums), see Introducing Runsums.
For sums of odd numbers see Runs of Odd Numbers
  1. What are the starting and ending numbers of the run of n natural numbers centered on n when n is odd? For example: 3+4+5+6+7 is a run of length 5 centred on the number 5, starting at 3 and ending with 7. What is special about their sums?
    Answer For a run of 2k+1 natural numbers centered on 2k+1, the first is k+1 and the last is 3k+1 with a sum of (2k+1)²
    The sums are the square of (the odd number) n
  2. Find a formula for the sum of n numbers beginning at n. The list of these sums starts: 1, 5, 9, 18, 25, 39, A110349.
    Answer if the starting number is odd: 2n-1 + 2n + ... + 2n+(2n-2) = (2n-1)²
    If the starting number is even: 2n + 2n+1 + ... 2n+(2n-1) = 4n² + n
  3. Find all the runs of odd numbers with a sum of 2025. (Hint: See the sums of odd numbers link above for an easy method to do this.)
    Answer 1: 2025 =1+3+...+87+89 ≡ 1⊕89 ≡ 45⊗45 = 452
    2: 2025 =49+51+...+99+101 ≡ 49⊕101 ≡ 27⊗75 = 512−242
    3: 2025 =57+59+...+103+105 ≡ 57⊕105 ≡ 25⊗81 = 532−282
    4: 2025 =121+123+...+147+149 ≡ 121⊕149 ≡ 15⊗135 = 752−602
    5: 2025 =217+219+...+231+233 ≡ 217⊕233 ≡ 9⊗225 = 1172−1082
    6: 2025 =401+403+405+407+409 ≡ 401⊕409 ≡ 5⊗405 = 2052−2002
    7: 2025 =673+675+677 ≡ 673⊕677 ≡ 3⊗675 = 3392−3362
    8: 2025 =2025 ≡ 2025 ≡ 1⊗2025 = 10132−10122
  4. 2025 is the sum of the first n primes that are of the form 4k+1. The list of primes with this form begins 5, 13, 17, 29, ... .
    What is n if the sum of 2025?
    Answer n=21: 2025= 5+13+17+29+37+41+53+61+73+89+97+101+109+113+137+149+157+173+181+193+197
    For other n, see A038346

Early Bird Numbers

We write out all the numbers in order as a single list of digits one after the other with no gaps, called the Natural Number Sequence. Clearly all numberswill eventually appear but some numbers appear before their "natural" place in the sequence, such as 21 which is the end of 12 and the start of the next number 13.
These are called Early Bird numbers.
For more on the Natural Number Sequence and Early Bird numbers, see An Introduction to the Natural Number Sequence 0123456789101112...

There are Early Bird numbers in other concatenated sequence of digits, such as using the binary representatons of each natural number, or another base.

  1. Where does 2025 first appear in the Natural Number sequence: in its "natural" place or before?
    Answer As a sequence of the decimal digits, 2025 first appears in its "natural" position ... 2024 2025 2026 ... (positions 20229..20239)
  2. What if we write the numbers out in order with no gaps, as before, but in binary?
    The Binary Number Sequence starts (without the gaps): 0 1 10 11 100 101 110 ... .
    Where does the binary for 2025 = 111111010012 first appear now?
    Answer 2025 in binary first appears at positions 1696..1706 in numbers 243 244 245: 11110011 11110100 11110101

Clock puzzles

  1. 20:25
    At 8:25pm a digital 24-hour clock shows 20:25. Ignoring the colon (:), which other square numbers will it show every day?
    Answer 0, 1, 4, 9, 16, 25, 36, 49, 100, 121, 144, 225, 256, 324, 400, 441, 529, 625, 729, 841, 900, 1024, 1156, 1225, 1444, 1521, 1600, 1849, 1936, 2025, 2116, 2209, 2304
    33 in all. see A122541
  2. 00:20:25
    If we had a digital clock showing seconds also, then both 00:20:25 = 2025 = 45² and 20:25:00 = 202500 = 450² are square numbers. How many times will it show a 6-digit square number now and what is the largest?
    Answer There are 217 squares shown on the 6-digit 24-hour clock, from 00:00:00 = 0² up to 23:52:25 = 485²
    In Mathematica we have
    Clear[IsClockSec]; (* n can be seen on a digital 24 hour clock as hhmmss *) IsClockSec[n_] := Block[{digs = IntegerDigits[n]}, digs = Join[Table[0, 6 - Length[digs]], digs]; MemberQ[{0, 1, 2}, digs[[1]]] && If[digs[[1]] == 2, MemberQ[{0, 1, 2, 3}, digs[[2]]], True] && MemberQ[{0, 1, 2, 3, 4, 5}, digs[[3]]] && MemberQ[{0, 1, 2, 3, 4, 5}, digs[[5]]] ]; Select[Table[n -> n^2, {n, 0, Sqrt[240000]}], IsClockSec[#[[2]]] &] Length[%]

© 2024 Created: 24 December 2024
Dr Ron Knott

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