Matrices: Addition and Subtraction
(
0
6
–1
3
)
–
(
4
5
–3
–2
)
=
(
)
Worked Solution:
Subtract the numbers in the same positions in each matrix:
(
0
6
–1
3
)
–
(
4
5
–3
–2
)
=
(
0 – 4
6 – 5
–1 – (–3)
3 – (–2)
)
=
(
–4
1
2
5
)
©
MEI Produced by Dr Ron Knott, 15 February 2004
Test reference:
MatrixAddSub.html?ref=69937